D(p)=-3p^2-7p+700

Solution for D(p)=-3p^2-7p+700 equation:

(D)=-3D^2-7D+700

We move all terms to the left:

(D)-(-3D^2-7D+700)=0

We get rid of parentheses

3D^2+7D+D-700=0

We add all the numbers together, and all the variables

3D^2+8D-700=0

a = 3; b = 8; c = -700;
Δ = b2-4ac
Δ = 82-4·3·(-700)
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$D_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-92}{2*3}=\frac{-100}{6}
=-16+2/3
$
$D_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+92}{2*3}=\frac{84}{6}
=14
$